X^2+4x=x-5

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Solution for X^2+4x=x-5 equation: 



X^2+4X=X-5

We move all terms to the left:

X^2+4X-(X-5)=0

We get rid of parentheses

X^2+4X-X+5=0

We add all the numbers together, and all the variables

X^2+3X+5=0

a = 1; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·1·5
Δ = -11
Delta is less than zero, so there is no solution for the equation

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